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The Antilogarithm Calculator will calculate:

- The antilogarithm of a number.
- The antilogarithm of a number rounded to the correct number of significant figures determined by the input.
- The antilogarithm of a number rounded to the correct number of decimal places as determined by user input (default is 4 decimla places).

**Antilogarithm Calculator Parameters:** Antilogarithm cannot be negative;

The antilogarithm (A) of is |

The antilogarithm (A) of to decimal places is |

The antilogarithm (A) of to significant numbers is |

Antilogarithm Calculations |
---|

A = 10^{a}A = 10 ^{}A = |

Antilogarithm Calculator Input Values |

Number (x) = |

Please note that the formula for each calculation along with detailed calculations is shown further below this page. As you enter the specific factors of each antilogarithm calculation, the Antilogarithm Calculator will automatically calculate the results and update the formula elements with each element of the antilogarithm calculation. You can then email or print this antilogarithm calculation as required for later use.

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If log A = x, then A is called the antilogarithm of x and is written as A = antilog x.

For example, if log 1000 = 3 (because 10^{3} = 1000), then antilog 3 = 1000. In simpler words, the term "antilogarithm" is an alternative version of "10 in power ".

If A is negative, the value of antilogarithm is smaller than 10 but it is always positive anyway. For example, antilog (-2) = 0.01 because 10^{-2} = 1 / 100 = 0.01.

The value of antilogarithm is not always that simple. If we have to find the antilogarithm of a decimal number, the result may be a real number with an infinite number of decimal places. Therefore, we may need to round the result to a certain number of decimal places. However, this may cause confusion, as different users may round the result to different decimal places. Hence, it is useful to appoint some rules in rounding such numbers. The most suitable rule in this regard is to express the result in the same number of significant figures as the antilogarithm input.

For example, if we have to calculate antilog 5.32, we must express the result in 3 significant figures because 5.32 has 3 s.f. We have

antilog 5.32 = 10^{5.32} = 208,929.6130854039.

Since the result is a real number with an infinite number of digits after the decimal place, we have to round the answer to 3 significant figure to fit the input. Hence, based on the rounding rules and those of significant figures, we obtain

antilog 5.32 ≈ 209,000

where only the first three digits are significant, as this is a whole number and trailing zeroes are not significant.

This approach is also used in negative numbers. For example,

antilog(-3.147) = 10^{-3.147} = 0.00071285303.

However, we cannot write the result in this way. Since -3.147 has four significant figures, we must write the result accordingly (leading zeroes are not significant). Hence, applying the known rounding rules, we obtain

antilog(-3.147) ≈ 0.0007129

This is because the digit on the right of 8 is 5 (5 > 4), so 8 becomes 9.

The following Math tutorials are provided within the Approximations section of our Free Math Tutorials. Each Approximations tutorial includes detailed Approximations formula and example of how to calculate and resolve specific Approximations questions and problems. At the end of each Approximations tutorial you will find Approximations revision questions with a hidden answer that reveal when clicked. This allows you to learn about Approximations and test your knowledge of Math by answering the revision questions on Approximations.

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