Please provide a rating, it takes seconds and helps us to keep this resource free for all to use
Welcome to our Math lesson on Systems of Inequalities where one inequality is Quadratic and the other is Linear, this is the fourth lesson of our suite of math lessons covering the topic of Systems of Inequalities, you can find links to the other lessons within this tutorial and access additional Math learning resources below this lesson.
When solving systems of inequalities where not all are linear (for example, when one inequality is quadratic), we use the same approach as in systems of linear inequalities. The only difference is that one of the lines is a parabola, so the solution zone has one curved side.
Another thing to point out in such systems is that if we are interested to find any minimum or maximum point as in the previous examples, we must solve the corresponding system of equations only by substitution method. Thus, one of the variables in the linear equation is expressed in terms of the other variable and we substitute it in the quadratic equation. Let's consider an example to clarify this point, where theory and exercise are combined to have a better understanding.
Solve the following system of inequalities.
First, we identify the direction of the solution set for the linear inequality. We do this by writing the first inequality in the form y (?) mx + n. Thus,
Hence, the solution zone of this inequality alone lies under the graph's line y = 3x/2 - 1/2.
On the other hand, the quadratic equation is already in its regular form y (?) ax2 + bx + c, where a = 1, b = -2 and c = 1, while the inequality symbol which replaces the question mark is " ≥ ". This means the solution zone lies above the parabola's graph.
The best thing to do is to solve the system of the corresponding equations. The number of solutions depends on the sign of the discriminant obtained when the linear equation is substituted into the quadratic one. In the specific case, we have
We can write 3x - 1 = 2y, multiply the quadratic equation by 2 and then express y in the quadratic equation in terms of x. In this way, we obtain
This is a second-order equation with one variable, where its roots represent the intercept of the two original graphs. We have a = 2, b = -7 and c = 3. Thus, the discriminant Δ is
Since the discriminant is positive, we have two intercepts for our graphs. Their x-coordinates are found by solving the second-order equation above. Expressing the two intercepts by A and B respectively yields
and
The corresponding y-values for points A and B are
Hence, the two intercepts are A(0.5, 2.25) and B(3, 4).
Another important point of the solution set that helps identify (in this case) the lowest point of the solution set is the parabola vertex. We have briefly discussed this point in previous tutorials, where the formulas used to find the vertex V of a parabola are
Substituting the known values for the original quadratic equation (a = 1, b = -2 and c = 1) yields
and
Hence, point V(1, 0) is the vertex of the parabola, which at the same time acts as the lowest point of the solution set for the original system of inequalities.
The graph solution for the system is shown below.
We can draw the following conclusions by looking at the graph:
We can use the same approach for systems with more than two inequalities, where not all of them are linear.
Enjoy the "Systems of Inequalities where one inequality is Quadratic and the other is Linear" math lesson? People who liked the "Systems of Inequalities lesson found the following resources useful:
Please provide a rating, it takes seconds and helps us to keep this resource free for all to use
We hope you found this Math tutorial "Systems of Inequalities" useful. If you did it would be great if you could spare the time to rate this math tutorial (simply click on the number of stars that match your assessment of this math learning aide) and/or share on social media, this helps us identify popular tutorials and calculators and expand our free learning resources to support our users around the world have free access to expand their knowledge of math and other disciplines.