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Math Lesson 7.4.3 - Properties of Surds

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Welcome to our Math lesson on Properties of Surds, this is the third lesson of our suite of math lessons covering the topic of Surds, you can find links to the other lessons within this tutorial and access additional Math learning resources below this lesson.

Properties of Surds

Surds have four main properties, where the first two are identical to the properties of roots we have discussed in tutorial 7.2. Let's list them below.

Surds property 1

For any positive numbers a and b (or they may also be negative when n is odd), we have

√(n&a ∙ b) = a ∙ √(n&b)

For example,

√6 = √(2 ∙ 3) = √2 ∙ √3

This rule is used in situations that require simplification such as those presented below.

Example 3

Write the simplest form of the expressions:

  1. √21/√6
  2. √105/√10 ∙ √3

Solution 3

  1. From the first property of surds, we have
    √21/√6 = √(3 ∙ 7)/√(2 ∙ 3)
    = (√3 ∙ √7)/(√2 ∙ √3)
    = √7/√2
  2. Again, from the first property of surds, we have
    √105/√10 ∙ √3 = √(3 ∙ 35)/√(2 ∙ 5) ∙ √3
    = √(3 ∙ 5 ∙ 7)/√(2 ∙ 5) ∙ √3
    = √3 ∙ √5 ∙ √7/√2 ∙ √5 ∙ √3
    = √7/√2

Surds property 2

For any positive numbers a and b (or they may also be negative when n is odd), we have

a/b = a/b

For example,

∛(27/8) = ∛27/∛8
= ∛(33 )/∛(23 )
= 3/2

Example 4

Write the simplest form of the expressions:

  1. 16/81
  2. 88/33

Solution 4

  1. From the second property of surds, we have
    ∜(16/81) = ∜16/∜81
    = ∜(24 )/∜(34 )
    = 2/3
  2. Again, from second property of surds (combined with the first one), we have
    √(88/33) = √88/√33
    = √(8 ∙ 11)/√(3 ∙ 11)
    = √8 ∙ √11/√3 ∙ √11
    = √8/√3

Surds property 3

For any numbers a and b where b is positive, we have

a/√b = a√b/b

Indeed,

a/√b = a ∙ √b/√b ∙ √b = a ∙ √b/(√b)2 = a√b/b

For example,

6/√3 = 6√3/√3 ∙ √3
= 6√3/3
= 2√3

This property is also known as "rationalisation of denominator", for which we will discuss extensively in the next tutorial.

Example 5

Write the following expressions in the simplest form.

  1. 5/2√2
  2. 12/√6

Solution 5

  1. From the third property of surds (also in combination with the first two), we have
    5/2√2 = 5 ∙ √2/2√2 ∙ √2
    = 5 ∙ √2/2 ∙ (√2)2
    = 5 ∙ √2/2 ∙ 2
    = 5 ∙ √2/4
  2. Again, from the third property of surds (also in combination with the first two), we have
    12/√6 = 12 ∙ √6/√6 ∙ √6
    = 12 ∙ √6/(√6)2
    = 12 ∙ √6/6
    = 2√6

Surds property 4

For any numbers a, b and positive c (or it can also be negative when n is odd), we have

ac ± bc = (a ± b)c

This property derives from adding or subtracting with like term approach mentioned earlier in this tutorial.

For example,

7√2 - 3√2
= (7 - 3) √2
= 4√2

Example 6

Write the following expressions in the simplest terms.

  1. √112 - √28/√252
  2. √50 + √18/5√8

Solution 6

  1. From the fourth property of surds, in combination with the other three, we have
    (√112 - √28)/√252
    = √(16 ∙ 7) - √(4 ∙ 7)/√(36 ∙ 7)
    = √16 ∙ √7 - √4 ∙ √7/√36 ∙ √7
    = 4√7 - 2√7/6√7
    = √7 (4 - 2)/3 ∙ √7
    = 2√7/3√7
    = 2/3
  2. Again, applying the fourth property of surds in combination with the other three, yields
    √50 + √18/5√8
    = √(25 ∙ 2) + √(9 ∙ 2)/5 ∙ √(4 ∙ 2)
    = √25 ∙ √2 + √9 ∙ √2/5 ∙ √4 ∙ √2
    = 5√2 + 3√2/5 ∙ 2√2
    = (5 + 3) √2/10√2
    = 8√2/10√2
    = 8/10
    = 4/5

More Surds Lessons and Learning Resources

Powers and Roots Learning Material
Tutorial IDMath Tutorial TitleTutorialVideo
Tutorial
Revision
Notes
Revision
Questions
7.4Surds
Lesson IDMath Lesson TitleLessonVideo
Lesson
7.4.1What Are Surds?
7.4.2What are the different Types of Surds
7.4.3Properties of Surds
7.4.4Basic Operations with Surds

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